7/2     How do people pronounce C++'s "operator()"?
        \_????? Do you mean you are overloading the empty constructor?
           \_ Hi.  You are stupid.
              \_ Hi dickwad, how's how's life going being a constant
                 asshole? Anyway, I found the answer, it's called a
                 "function call operator" if OP meant foo(a,b). Since
                 OP was somewhat ambigious it could also refer to overloading
                 the cast operator.
                 \_ Actually, it couldn't. Unless OP didn't know what he
                    was talking about, of course. There seems to be a lot
                    of that going around.
                    \_ Agreed, since it would require the casting rvalue
                       notation in front of it to be overloading casting.
                       However, given the attitude of people on MOTD these
                       days they could've said "oh, well, what I meant
                       was..." and wiggle their way out of it. Anyway,
                       I certainly hope OP isn't overloading () on a regular
                       basis. Thanks for reminding me what a dog the
                       language of C++ is.
                       \_ Correction, /rvalue/type.