10/15   Alright, another perl question (I'm learning...)
        I have a 2D hash of refernces to hashes; is there some way to do the
        following in one line?
                my $ref = $myHash{"a"}{"1"};
                my $dataVal = $$ref{$someIndex};
        Thanks alot.
        \_ I think you want
                my $val = $myhash{a}{1}{$someIndex}
           assuming you have something like
                %myhash = (
                    'a' => {
                        '1' => {
                            'someIndex' => 'someValue'
                        }
                    }
                );
            Basically any hash (or array) dereferences after the first
            assume that you're accessing a reference to an array or hash.
            This means that $foo->{bar}->[baz]->{garply} is equivalent to
            $foo->{bar}[baz]{garply}.  Note that the first dereference
            requires the -> operator if $foo is a reference (in this case,
            to a hash).  Confused yet? -geordan
            \_ Yeah I'm confused.  Where the hell did you come up with garply?
               \_ 'garply' the word or 'garply' the key to an anonymous
                  hash in an anonymous array in an anonymous hash in
                  a hashref?  (Heh.) -geordan
            \_ Actually, I think that makes sense. Thanks. I was trying this:
                   my $val = $$myhash{a}{1}{$someIndex};
               which is more like what I would do if it was a scalar with a
               reference... but I think I understand the distinction now. cool.
                                                                        - op