11/12 On paper, how do you figure out what log_2 (4/3) is? I remember
log_2 (4/3) = log_2 4 - log 3 = 2 - log 3. Now what?
\_ 2 - log_2 3 = 2 - ln 3 / ln 2. Then get a mathematical table and
look up ln 3 and ln 2. Or use a polynomial of ln(1+x). I forgot
the polynomial. --- yuen
\_ ln(1+x) = x + x^2/2 + x^3/3 + x^4/4 + ..., for |x| < 1.
As another poster pointed out, log_2(4/3) = ln(4/3)/ln(2)
\_ That polynomial is wrong. Try ln(1 + 0.9).
\_ It should be ln(1+x) = x/1 - x^2/2 + x^3/3 - x^4/4 + ...
\_ that was remarkably useless.
\_ How else would you do that?
\_ perhaps they mean the question, and therefore the whole
\_ real? imaginary? quaternion? octonion?
thread is useless, which it is.
\_ Here:
log_X (Y) = log_anything(Y) / log_anything(X)
where anything is, well, any number.
\_ real? imaginary? quaternion? octonion? sedenion?
\_ Yes, for any reasonable definition of the "log_X (Y)" symbol
over these domains. For domains more general than positive
reals where a "log" is still definable, Log becomes
multivalued... which only results in the above
holding for "some appropriate" branch thereof. -alexf
\_ Damn, look who looked at a fancy math book
for a few hefty terms. I'm surprised you were
even able to spell those words correctly.
\_ If you wanted to show off, you could simply say
"non-positive?" instead of throwing out all the other terms.
Besides, you should've said "complex?" instead of "imaginary?"
to make your progression of terms correct.
\_ alexf insults deleted
\_ But then how do you proceed on paper? Same problem.
\_ how accurate do you need to be? you can get a rough approximation
using differentials.
\_ just use a fucking calculator.
\_ no calculator on the GRE |