Berkeley CSUA MOTD:Entry 22569
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2025/05/24 [General] UID:1000 Activity:popular
5/24    

2001/9/21 [Computer/SW/Languages/C_Cplusplus, Computer/Theory] UID:22569 Activity:nil
9/20    How do I pass a pointer to a member function in C++?
        I'm trying to use mergesort (stdlib.h) like this
        mergesort(array, arrLength, sizeof(int), intCompare);
        where intCompare is my comparison function-- but I'd like to put
        intCompare into a class.  But
        mergesort(array, arrLength, sizeof(int), MyClass::intCompare);
        doesn't work.  How do I do this?
        \_ You can't.
        \_ You can't because a member function is not quite a function in a
           sense you are used to.  You see, all member functions implicitly
           assume a 'zeroth' argument, which is always the object on which
           this member function is invoked.  In general, you do not know the
           identity of this object at compile time, and even if you did, there
           is really no syntax in C++ to allow you to specify this information
           in the function pointer type.  What you want is to create a wrapper
           function, which calls the member function on an appropriate object.
           Then you can pass the pointer to the wrapper function to your
           mergesort routine.  It's worth noting that object oriented languages
           with closures and curried functions, like ocaml, avoid this
           problem altogether.  -- ilyas
2025/05/24 [General] UID:1000 Activity:popular
5/24    

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