4/35 Does aluminum foil or white sheets of paper reflect more light, if the
direction of the reflected light is not important? -- yuen
\_ Are you talking about strictly visible light? IR? UV?
\_ I'm interested in daylight (5500K). -- yuen
\_Christ, get a clue. Get a strong light source and a dark wall.
Hold up a sheet of paper and a sheet of tin foil that are the
same size. Measure the size of the square of reflected light.
Estimate the intensity in a small area, and multiply by the
entire area of the reflected light. Very simple. Any fourth
grader could do it.
\_ WAG (wild-ass-guess): Metal over paper any day. However, to test,
put some paper and aluminum foil out in the sun for a few hours. See
which is warmer.
\_ This is incorrect advice. Just because something 'feels' warmer
does not mean it is. For instance, titanium watches feel
neutral on your hand, but steel watches feel cold (when you first
put them on). However, both are at the same (room) temperature.
The subjective sensation of coldness can often be caused by the
_rate_ of heat transfer, not the actual temperature. In the case
of watches, steel has a greater heat transfer rate, so it absorbs
more heat from the human skin in the same amount of time than
titanium. These rapid temperature changes is what the human
skin's thermal receptors are most sensitive to.
-- motd physics god
\_ i knew this, too. - motd physics weenie
\_ as tom pointed out on wall, this won't work for another
good reason: paper transmits light, aluminum doesn't.
so you need to check the temperature as well as the trasmitted
light. -ali
\_ take both into a dark room and flash a flashlight at them...
have it reflect against a wall. seems like a logical
test *shrug*
\_ this doesn't take into consideration the fact that aluminum
is specular and paper diffuse. the pattern on the wall will
look different. you need to add the TOTAL amount of energy
\_ Who cares?
reflected everywhere on the wall, not just look at the intensity
at one point on the wall. the only good quick way i can think
of this is to point a thin laser at the paper, measure the
reflected intensity at some angle, and scale to the rest of the
hemisphere, and do the same with aluminum, but measure the
reflected intensity near the surface normal. -ali
\_ The two sides of my foil differ. Which side you talking 'bout?
\_ If you want to grow pot, don't use aluminum foil. _Very_ hard to keep
flat enough to reflect light.
\_ I think of it this way - mirrors are made of melted metal (I don't
know which) poured over the back of glass. Mirrors are *very*
reflective. I believe that part of the reason is that the glass
holds the metal flat. Put paper on the back of glass, and you
don't get anything particularly reflective. If my life depended
on it, I'd choose aluminum. |