3/24    Can you have nested parenthesis in perl regular expressions?
        If so, what is the rule for assigning the corresponding $d variables?
        \_ Yes: you count open parens.  So in /(foo(bar))/, $1 is "foobar"
           and $2 = "bar".
        \_ no.
           \_ yes.
              \_ xor.
        \_ Why don't you post the code and what you _think_ it should do and
           maybe you'll get a real answer.  Perl being perl, your question can
           be interpreted in more than one way.